Dr Grzegorz Hoppe

Zbiór liczb N(210)

Jeżeli:

N210 = {2Nᴜ{0}} x {3Nᴜ{0}} x {5Nᴜ{0}} x {7Nᴜ{0}}

Pu = (P ∪ {1})\{2,3,5,7}

 

To:

N = N210 ᴜ {(6N + 5N210)} ᴜ {(6N + 7N210)}

N = N210 x ({1} ᴜ (6(Pu ᴜ (Pu x Pu) + {5})) ᴜ (6(Pu ᴜ (Pu x Pu) + {7})))

N = N210 x ({1} ᴜ (6Pu + {5,7}) ᴜ (6(Pu x Pu) + {5,7}))

N2 = N210 x ({2} ᴜ 6(Pu ± {1}) ᴜ 6((Pu x Pu) ± {1}))

N2 = {2} x N210 x ({1} ᴜ 3(Pu ± {1}) ᴜ 3((Pu x Pu) ± {1}))